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x^2+11x-30=180
We move all terms to the left:
x^2+11x-30-(180)=0
We add all the numbers together, and all the variables
x^2+11x-210=0
a = 1; b = 11; c = -210;
Δ = b2-4ac
Δ = 112-4·1·(-210)
Δ = 961
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{961}=31$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(11)-31}{2*1}=\frac{-42}{2} =-21 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(11)+31}{2*1}=\frac{20}{2} =10 $
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